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[xsl] sequential numbering in xslt

Subject: [xsl] sequential numbering in xslt
From: a kusa <akusa8@xxxxxxxxx>
Date: Sun, 3 Jan 2010 14:41:45 -0600
Hi:

I cannot post the input , output and XSLT since they are too big and
complicated, So I apologize and will try to explain my problem
conceptually.
 I have a number of XML files as input, and I transform them into
another XML format using XSLT. The output XML file has a schema and
has a required 'seq' attribute in the root element that needs to be
incremented for each input XML file.

So, for example, if I had 5 input xml files a.xml, b.xml, c.xml,
d.xml, e.xml, and I transformed them into Aout.xml, Bout.xml,
Cout.xml, Dout.xml and Eout.xml , the output of which looks something
like below:
Output XML:

<car seq="1">
<req>....<req>

<body id="c1">

</body>

</car>


for every input file, in the transformation, I want to increment
attribute 'seq' in the output file by 1 when I transform the input
files using xslt.
I  have tried <xsl:number> and tried writing a function. But the
problem is that since variables in xslt are constants, there is no way
to increment a number, store it in a temp variable and increment it
for the next time in xslt 2.0 unlike procedural languages like C or
C++.

Is there any other way of achieving this in XSLT 2.0?

Please advise on any other approach.

Thanks in advance.
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RE: [xsl] Unparsed-text-available r, Michael Kay Thread Re: [xsl] sequential numbering in x, G. Ken Holman
Re: [xsl] Unparsed-text-available r, Syd Bauman Date Re: [xsl] sequential numbering in x, G. Ken Holman
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