Re: [xsl] another placement of nodes question

[Martin Honnen <Martin.Honnen@xxxxxx>]

a kusa wrote:

> Source XML:
>
> <root>
> <level1>
> <st1>
> <desc><text>sample desc</text></desc>
> <!-- A <spec> element can occur here as well-->
> <level2>
> <item><text>r1 </text></item>
> <item><text>r2</text></item>
> </level2>
> <spec><para>Some spec 1</para></spec>
> <spec><para>Some spec 2</para></spec>
> </st1>
> </level1>
> </root>
>
> Here is my desired output XML:
>
> <root>
>
> <step1>
> <text>sample desc</text>
>
> <step2>
> <text>r1</text>
> </step2>
>
> <step2>
> <text>r2</text>
> <spec><para>Some spec 1</para></spec>
> <spec><para>Some spec 2</para></spec>
>
> </step2>
>
> </step1>
> </root>
>
> Please note that every item under level2 becomes a step2 in my output XML.

The following stylesheet creates the output you describe from the input 
you posted:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  version="1.0">

  <xsl:output indent="yes"/>
  <xsl:strip-space elements="*"/>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="st1/desc | st1/level2">
    <xsl:apply-templates/>
  </xsl:template>

  <xsl:template match="level1">
    <step1>
      <xsl:apply-templates select="st1/*"/>
    </step1>
  </xsl:template>

  <xsl:template match="level2/item">
    <step2>
      <xsl:apply-templates/>
    </step2>
  </xsl:template>

  <xsl:template match="level2/item[last()]" priority="3">
    <step2>
      <xsl:apply-templates/>
      <xsl:copy-of select="../following-sibling::spec"/>
    </step2>
  </xsl:template>

  <xsl:template match="st1/spec"/>

</xsl:stylesheet>

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/