Subject: Re: [xsl] Applying external XML From: Israel Viente <israel.viente@xxxxxxxxx> Date: Tue, 2 Feb 2010 20:40:07 +0200 |
Try to use absolute paths in menu.xml or do something like: <xsl:for-each select="item-uri"> <xsl:variable name="fileName" select="normalize-space(.)"/> <xsl:variable name="infile" select="concat('file:///',$infilepathname, '/', $fileName)" /> <xsl:apply-templates select="doc($infile)"/> </xsl:for-each> Israel On Tue, Feb 2, 2010 at 8:29 PM, Rob Belics <rob_belics@xxxxxxxxxxx> wrote: > > I'm trying to import xml data from other files on a remote server and > apply templates to that data. Everything in my "restaurant.xsl" works > and I've retrieved "menu.xml" which contains links (item-uri) to other > xml files (item.xml) that contain more info about each item for sale on > the menu (tuna and roast beef). However, I'm having problems trying to > import the item.xml data. > > I tried <xsl:apply-templates select="document()" /> in between the > 'for-each' with various combinations of xpath for the document() but > that hasn't gotten results I need. > > restaurant.xsl: > <xsl:template match="menu"> > <menu> > <xsl:for-each select="item-uri"> > <!-- What goes here? Should I be using 'for-each'? --> > </xsl:for-each> > </menu> > </xsl:template> > > menu.xml: > <menu> > <item-uri>tuna.xml</item-uri> > <item-uri>roast-beef.xml</item-uri> > </menu> > > item.xml: > <order> > <size> > <name>Tuna</name> > <price>5.00</price> > </size> > </order>
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