Subject: Re: [xsl] xsl:include statement is "unexpected element". From: Lionel Villard <villardml@xxxxxxx> Date: Thu, 11 Mar 2010 14:38:15 -0500 |
Is there a way to package and include templates at a level lower than child-of-stylesheet-or-transform?
it seems that you are looking for conditional stylesheet inclusion, which can't be done in XSLT 1.0.
<xsl:include href="module-A.xsl" use-when="system- property('xsl:vendor')='vendor-A'"/>
Martin -
Ah HA!
I have it several levels down, which is undoubtedly the problem: <xsl:stylesheet>... <xsl:template>... <xsl:if>... <xsl:include>...
It must be a child, and not a descendant, apparently. Thank you.
Is there a way to package and include templates at a level lower than child-of-stylesheet-or-transform?
Very much appreciate the help.
Tim
On Thu, Mar 11, 2010 at 11:13 AM, Martin Honnen <Martin.Honnen@xxxxxx> wrote:Tim Hibbs wrote:
Attempting my first use of <xsl:include> as <xsl:include
href="calledTemplatesFO/ct_AddTableHeader.xsl">. XML Spy indicates the
file
is not valid, with the note
"Unexpected element
xsl:include"
Including file starts thusly:
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl=" http://www.w3.org/1999/XSL/Transform" xmlns:fo=" http://www.w3.org/1999/XSL/Format" xmlns:frq=" http://www.fedex.com/schemas/freightRateQuotation" exclude-result-prefixes="frq">
Where exactly have you placed the xsl:include? It needs to be a child of the xsl:stylesheet root element.
--
Martin Honnen http://msmvps.com/blogs/martin_honnen/
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