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Subject: Re: [xsl] modify the tag name of a given List Node From: Red Light <skydelta98@xxxxxxxxx> Date: Fri, 23 Apr 2010 10:35:34 -0700 (PDT) |
Hi Martin ,
(sorry i'm still a noob at xslt programming !)
i got my xsl template file like this :
<xsl:template match="/rapport">
<!-- here i got my main xsl elements -->
.
.
.
.
<!-- this doesn't work -->
<fo:table-row width="100%" >
<fo:table-cell padding="0.1cm">
<fo:block text-align="center" font-size="10.0pt" >
<xsl:choose>
<xsl:when test="(/rapport/content/projectDetails/keyword/keywordDetails/key0)">
<xsl:value-of select="/rapport/content/projectDetails/keyword/keywordDetails/key0"/>
</xsl:when>
</fo:table-cell>
</fo:table-row>
</xsl:template>
<xsl:template match="keywordDetails">
<xsl:copy>
<xsl:apply-templates select="key"/>
</xsl:copy>
</xsl:template>
<xsl:template match="key">
<xsl:element name="key{position()}">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:template>
if my understanding is write <xsl:copy-of select="node()"/> will replate the node and i should
<keywordDetails><key1>.............
now it doesn't work , am i missing something ?
and thanks
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