Re: [xsl] Trouble transforming special characters

[Craig Whisenhunt <craig@xxxxxxxxxxxx>]

Hi Martin,

Thanks for the quick reply.

Is there a way for me to do this without character maps such that I
don't have to change the XSL processor? I may not be in a position to
switch to Saxon 9.

Thanks again,
-Craig

On Tue, Aug 10, 2010 at 10:42 AM, Martin Honnen <Martin.Honnen@xxxxxx> wrote:
> Craig Whisenhunt wrote:
>>
>> Hello,
>>
>> I am transforming XML to HTML. The XML source has:
>>
>> Pe&ntilde;a
>>
>> which should transform and display as Peqa.
>>
>> Instead, the '&ntilde;' gets transformed into a '?'.
>>
>> Same problem with mdash
>>
>> Processor Information:
>> XSL version: 1
>> Vendor: Microsoft
>> Vendor URL: http://www.microsoft.com
>>
>> Using VS2008, C#, .NET 3.5
>>
>> My XSLT begins with:
>>
>> <?xml version="1.0" encoding="UTF-8"?>
>> <xsl:stylesheet version="2.0"
>> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; xml:space="default"
>> xmlns:l="urn::tlc.state.tx.us.salsa.legdoc">
>>  <xsl:output method="html" encoding="UTF-8" use-character-maps="cm1"
>> indent="yes"/>
>>  <xsl:character-map name="cm1">
>>    <xsl:output-character character="&#160;" string="&amp;nbsp;"/>
>>    <xsl:output-character character="&#8212;" string="&amp;mdash;"/>
>>    <xsl:output-character character="&#233;" string="&amp;eacute;"/>
>>    <xsl:output-character character="&#241;" string="&amp;ntilde;"/>
>>  </xsl:character-map>
>
>
>> Note that when I do the transformation in XMLSpy, it works fine. Using
>> it in code, though, produces a '?'.
>
> I think I did explain elsewhere that XML Spy supports XSLT 2.0 (i.e
> xsl:character-map) while XslCompiledTransform is an XSLT 1.0 processor that
> does not support any XSLT 2.0 constructs.
> If you want to use XSLT 2.0 with .NET code then use Saxon 9
> (http://saxon.sourceforge.net/) or use AltovaXML tools
> (http://www.altova.com/altovaxml.html).
>
>
> --
>
>        Martin Honnen
>        http://msmvps.com/blogs/martin_honnen/