Subject: [xsl] Selecting all elements which have an attribute that matches a given pattern|
From: "Etheridge, Stephen" <stephen.etheridge@xxxxxxxxxx>
Date: Wed, 18 Aug 2010 08:57:36 +0100
Hi all and apologies if this has been dealt with previously, I searched the archives and FAQ but did not find anything that was close to my problem: I have an XML file (a schema in fact) that is many thousands of lines long and I need to edit it (i.e transform it). There are numerous elements of type <xs:element> all of which have a "name" attribute. Some of those name attributes end with the string "List", e.g. "MilkTypeList". For those elements, I want to apply a template to add an additional <xs:element>. I am having great trouble crafting the correct "match" for my <xsl:template>. I have tried contains() and matches() but my editor (Oxygen) states that those cannot be used as a pattern and my reading supports that. Can anyone help? Thanks Stephen Please help Logica to respect the environment by not printing this email / Pour contribuer comme Logica au respect de l'environnement, merci de ne pas imprimer ce mail / Bitte drucken Sie diese Nachricht nicht aus und helfen Sie so Logica dabei, die Umwelt zu sch|tzen. / Por favor ajude a Logica a respeitar o ambiente nao imprimindo este correio electronico. This e-mail and any attachment is for authorised use by the intended recipient(s) only. It may contain proprietary material, confidential information and/or be subject to legal privilege. It should not be copied, disclosed to, retained or used by, any other party. If you are not an intended recipient then please promptly delete this e-mail and any attachment and all copies and inform the sender. Thank you.