Re: [xsl] Best way of testing Hexadecimal value [xslt 1.0]

[David Carlisle <davidc@xxxxxxxxx>]

On 26/08/2010 10:30, pankaj.c@xxxxxxxxxxxxxxxxxx wrote:
> Hello all,
>
> I just did the following test for one of the requirement in my stylesheet.
> Though I am able to get the correct result but somehow I am not convinced
> with the approach. There must be better/correct way of doing this.
>
> source
> =====
> <label>#x2022</label><!--  HEXADECIMAL FOR BULLET  ACTUALLY WITH
> 'AMPERSAND' AND ; ADDED TO IT -->
>
> Test
> ====
>    <xsl:template match="label">
>   <xsl:copy>
>          <xsl:choose>
>          <xsl:when test=".='.'"><!-- ='.' IS LITERAL BULLET SYMBOL  -->

If you don't want to use a bullet character you can use the numeric 
reference, just as your source has done and test

. = '& # x 2 0 2 2 ;'

It's not really clear if that is what you are asking?

>          <!--  Do Something here  -->
>          </xsl:when>
>          <xsl:when test=".!='.'"><!-- ='.' IS LITERAL BULLET SYMBOL  -->

xsl:otherwise is of course more efficient than testing the negation 
which is repeating the test done in the previous clause.
>          <!--  Do Something different here  -->
>          </xsl:when>
>      </xsl:choose>
> <xsl:copy-of select="@*"/>
> <xsl:apply-templates/>
> </xsl:copy>
> </xsl:template>
>
> <xsl:when test=".= 'BULLET SIGN'">  doesn't seems to be nice to me. Is
> there any better way to test hexadecimal values.
> Apart from this is there a way of testing whether string is a digit or
> character<label>1.</label>  <label>a.</label>.
you can test if number(.)=number(.) If the string represents a number, 
this is true, if it is a non number it is the test NaN = NaN which is 
false.
> Not tested:
>
> I believe<xsl:when test=".='BULLET SIGN'">  will check for the literal
> string instead of something like [A-Za-z0-9]. I am using XSLT 1.0.
>
> Any thoughts will be appreciated.
>
> TIA,
> Pankaj
david

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