Subject: Re: [xsl] unction return value not a node? From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 08 Sep 2010 16:25:01 +0100 |
Hello,In the first case you are selecting a node in an input document and then giving the string value of its preceding sibling(s)
Sorry but XSLT 2.0 and XPath 2.0 book is more than 1000 pages, so I'm writing this:
I've this xpath expression that returns a node stored in a variable:
<xsl:variable name="x" select="($airTraveler/preceding-sibling::ota:AirTraveler[@PassengerTypeCode!='INF' and substring( concat( gal:normNames( ota:PersonName/ota:Surname ), concat( gal:normNames( ota:PersonName/ota:GivenName ),gal:normNames( ota:PersonName/ota:NamePrefix ))),1,16) = $srnNP16 ], $airTraveler)[1]"/>
then if I do
<xsl:value-of select="$x/preceding-sibling::ota:AirTraveler"/>
I obtain the preceding-sibling nodes.
but if I write this function to use the same xpath expression, quite complicated, in two places
<xsl:function name="gal:func"> <xsl:param name="airTraveler"/> <xsl:param name="srnNP16"/> <xsl:value-of select="($airTraveler/preceding-sibling::ota:AirTraveler[@PassengerTypeCode!='INF' and substring( concat( gal:normNames( ota:PersonName/ota:Surname ), concat( gal:normNames( ota:PersonName/ota:GivenName ),gal:normNames( ota:PersonName/ota:NamePrefix ))),1,16) = $srnNP16 ], $airTraveler)[1]"/> </xsl:function>
but when I write:
<xsl:variable name="x" select="gal:func($airTraveler, $srnNP16 )"/> <xsl:value-of select="$x/preceding-sibling::ota:AirTraveler"/>
I don't obtain any preceding sibling.
Could you tell me why?
Many thanks
Bartolomeo
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