Re: [xsl] Mapping from two sources

[Michael Kay <mike@xxxxxxxxxxxx>]

 On 01/10/2010 8:14 PM, sudheshna iyer wrote:

Grouping handles this well:

<xsl:for-each-group select="$doc1//OrderLine, $doc2//POOrderline" 
group-by="OLN">
<Oline>
<OLN><xsl:value-of select="current-grouping-key()"></OLN>
<xsl:copy-of select="current-group()/(FName, ID)"/>
</Oline>
</xsl:for-each-group>

Michael Kay
Saxonica

> I need to have two sources:
>
> input1 and input2.
>
> input1:
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <Order>
> 	<OrderLine>
> 			<OLN>1</OLN>
> 			<Fname>aa</Fname>
> 	</OrderLine>
> 	<OrderLine>
> 			<OLN>2</OLN>
> 			<Fname>bb</Fname>
> 	</OrderLine>	
> </Order>
>
>
> input2:
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <POOrder>
> 	<POOrderLine>
> 			<OLN>1</OLN>
> 			<ID>123</ID>
> 			<LName>aa</LName>
> 	</POOrderLine>
> 	<POOrderLine>
> 			<OLN>2</OLN>
> 			<ID>324</ID>
> 			<LName>bb</LName>
> 	</POOrderLine>	
> </POOrder>
>
> I need the output from both sources combined. Please note that first two elements are coming from input1 and thrid element is from input2. What is the
> optimal way of doing this?
>
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <OrderResponse>
> 	<Oline>
> 		<OLN>1</OLN>
> 		<Fname>aa</Fname>
> 		<ID>123</ID>
> 	</Oline>
> 	<Oline>
> 		<OLN>2</OLN>
> 		<Fname>bb</Fname>
> 		<ID>324</ID>
> 	</Oline>
> </OrderResponse>