Re: [xsl] Customizing DocBook numbering scheme using XSL (legal style)

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Dear Nestor,

There are a couple of things about your question that are confusing.

You are correct that you cannot parameterize the setting on
xsl:number/@level.

But you also say

> But I am stuck because I cannot change the element <xsl:number> without
> having to rewrite a new template from scratch.

without explaining why this is a problem.

The usual approach to customizing code (such as
the Docbook stylesheets you might download) is
indeed to write new templates, keeping them in a
separate layer that imports the generic logic,
overriding its templates selectively. So you
rewrite only what needs rewriting, while keeping
your customizations separate from a standard
distribution. The mechanism you would use is xsl:import.

But it's not clear from your message whether this
advice is even relevant, since you don't say much
about what kind of architectural issues you are dealing with.

So: what's wrong with rewriting the template? You
would have to do this anyway even if you could
parameterize the setting you wanted, since the
template as given doesn't accept a parameter. :-)

Cheers,
Wendell

At 04:57 AM 10/14/2010, you wrote:
> Hello,
>
> I'm using dblatex v. 0.2.12-4 (GNU/Linux Ubuntu Lucid 10.04 64bit).
>
> ===
>
> I'm trying to number DocBook document in the 'legal' (lawyer) style, to
> say:
>
> 1 Chapter one
>  Article 1. Article one
>  Article 2. Article two
> 2 Chapter two
>  Article 3. Article three (*not* 'one' again)
>  Article 4. Article four (*not* 'two' again)
>
> =
>
> **I would just like to change <xsl:number> element to have the attribute
> "level=any" on the title of a <section> element.**
>
> ===
> I have used code from
> http://www.dpawson.co.uk/xsl/sect2/N5758.html#d7876e154 (recommended
> here, but simplified)
>
> ===
>   <xsl:template match="sect1">
>       <xsl:number level="any" from="chapter" format="1. "/>
>       <xsl:apply-templates/>
>   </xsl:template>
> ===
>
> I have carefully read the documentation, and I understand how XSL works.
> I have tried many different solutions, from different sites, but I have
> got no positive results.
>
> I have read on the book that XSL works with parameters, so I have tried
> also the following (no positive result):
>
> <xsl:param name="section.number.level">any</xsl:param>
>
> and
>
> <xsl:param name="section.title.number.level">any</xsl:param>
>
> But I am stuck because I cannot change the element <xsl:number> without
> having to rewrite a new template from scratch.
>
> Any ideas? Thanks.
>
> --
> NC)stor Amigo Cairo -- www.aberi.org -- +34 687 967 481 (lu-vi, 9-13h)
> Presidente de la AsociaciC3n por la Libertad de la InformaciC3n


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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