Re: [xsl] question on EXSLT data partitioning

[Erwan AMOUREUX <erwan.amoureux@xxxxxxxxxxxxxxxxxxxxxxx>]

I had a good look at my xslt sheet and , i only use position in match key or
with other context in use.
Sorry for that, my only excuse it's a very bad cold...

But could you test that, please ?

My xml example
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="D:\Mes
documents\testxml\positioncle.xslt"?>
<a>
 <b>11</b>
 <b>12</b>
 <b>13</b>
 <b>14</b>
 <b>15</b>
 <b>16</b>
 <b>17</b>
 <b>18</b>
</a>


My XSLT example

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
 <xsl:key name="part" match="b[(position() - 1) mod 3!=0]"
use="generate-id(../b[(position() - 1) mod 3=0  and
((following-sibling::b)[position()&lt;3])[generate-id(.)=generate-id(current(
))]])"/>
 <xsl:template match="/">
  <r>
   <xsl:for-each select="*/b[(position() - 1) mod 3=0]">
    <c>
     <xsl:apply-templates select=".|key('part',generate-id(.))"/>
    </c>
   </xsl:for-each>
  </r>
 </xsl:template>
 <xsl:template match="b">
  <xsl:copy-of select="."/>
 </xsl:template>
</xsl:stylesheet>

I think it's too complicated and maybe it can be false but i'm curious to know
what you think about idea
----- Message d'origine -----
De : "Erwan AMOUREUX" <erwan.amoureux@xxxxxxxxxxxxxxxxxxxxxxx>
@ : <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Envoyi : jeudi 21 octobre 2010 09:36
Objet : Re: [xsl] question on EXSLT data partitioning


My mistake!
sorry
----- Message d'origine -----
De : "Michael Kay" <mike@xxxxxxxxxxxx>
@ : <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Envoyi : mercredi 20 octobre 2010 16:24
Objet : Re: [xsl] question on EXSLT data partitioning


>
>> For me it's logical
>> When you use global variable, current node is root, so with the key ,it's
the same thing and position is calculated with the root as initial context
>>
>
> Whether it's logical or not, the specification is quite clear. In XSLT 1.0:
>
> the expression specified in the use attribute of the xsl:key element is
> evaluated with x as the current node and with a node list containing
> just x as the current node list
>
> So position() in the use expression returns 1.
>
> Michael Kay
> Saxonica