Subject: Re: [xsl] Returning a value from a template From: Michael Kay <mike@xxxxxxxxxxxx> Date: Wed, 10 Nov 2010 09:00:08 +0000 |
<xsl:variable name="contains21"> <xsl:for-each select="/ns0:Transaction-850/ns0:Loop-N1"> <xsl:if test='ns0:Segment-N1/ns0:Element-66 = "21"'>*</xsl:if> </xsl:for-each> </xsl:variable>
Michael Kay Saxonica
I have been scratching my head on how to return a value from a called template which includes a for loop. A snippet of the XML fragment is as follows:
<Loop-N1> <Segment-N1> <Element-98>BT</Element-98> <Element-93 xsi:nil="true"/> <Element-66>21</Element-66> <Element-67>RA0129937</Element-67> </Segment-N1> </Loop-N1> <Loop-N1> <Segment-N1> <Element-98>ST</Element-98> <Element-93>ABC COLUMBUS DIVISION</Element-93> <Element-66>11</Element-66> <Element-67>RA0314562</Element-67> </Segment-N1> </Loop-N1>
The element<Loop-N1> can occur multiple times. If one of the<Element-66>'s contain a value of "21" then I need to generate a fixed string value else I need to generate another fixed string literal. So I tried creating a named template and calling this from my main template like a function:
<xsl:template name="getOrderSource">
<xsl:for-each select="/ns0:Transaction-850/ns0:Loop-N1"> <xsl:if test='ns0:Segment-N1/ns0:Element-66 = "21"'> <xsl:variable name="ordrSrc" select="NAEDI"/> </xsl:if> </xsl:for-each>
<xsl:choose> <xsl:when test='$orderSrc = "NAEDI"'> <xsl:text disable-output-escaping="no">NAEDI</xsl:text> </xsl:when> <xsl:otherwise> <xsl:text disable-output-escaping="no">NAEDIBrokerage</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:template>
This was called like: <corecom:ID> <xsl:call-template name="getOrderSource"/> </corecom:ID>
However, I realized that the variable declared inside the for-each is not visible to the xsl:choose that follows. What I was trying to do is to set a flag to indicate that the element exists and then return the appropriate string literal. Would there be a simpler way to do this? Thanks!
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