Subject: Re: [xsl] Accessing the XML file name from an XSL Transform From: Michael Kay <mike@xxxxxxxxxxxx> Date: Wed, 10 Nov 2010 14:29:50 +0000 |
Try the document-uri() function.
I need to access the filename (well, actually without the extension, but that's a simple RegEx) in an XSL Transform Obviously, I can pass a xsl:param name= to a XSLT transform that contains the filename, but I can't see how to achieve this when using Saxon's -s: command line option where -s: contains a directory and not a file.
I'm sure there's got to be a way to find out the XML doc name that's being transformed, but I just can't find it.
Michael Kay Saxonica
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Accessing the XML file name f, Neil Owens | Thread | RE: [xsl] Accessing the XML file na, Neil Owens |
[xsl] Accessing the XML file name f, Neil Owens | Date | Re: [xsl] How to remove unnecessary, Wolfgang Laun |
Month |