RE: [xsl] selecting nodes based on sibling values

Subject: RE: [xsl] selecting nodes based on sibling values
From: "Fabien Tillier" <f.tillier@xxxxxxxx>
Date: Tue, 23 Nov 2010 16:29:01 +0100
Hi Michael.
I don't know (I have so many fast answers already !!) which one is best, but
what is surprising me is how simple it seems once written...

Thanks a lot
Regards,
Fabien



-----Message d'origine-----
De : Michael Kay [mailto:mike@xxxxxxxxxxxx]
Envoyi : mardi 23 novembre 2010 16:25
@ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re: [xsl] selecting nodes based on sibling values


<xsl:variable name="gpsizes">
<xsl:for-each-group select="row" group-starting-with="row[level='40']">
<xsl:sequence select="count(current-group()) - 1"/>
</xsl:for-each-group>
</xsl:variable>
<xsl:value-of select="max($gpsizes)"/>

Michael Kay
Saxonica

On 23/11/2010 14:45, Fabien Tillier wrote:
> Hi List.
> Let's say I have an XML like below...
>
> <data>
> 	<row>
> 		<level>40</level>
> 		<keycode>1254.45.12</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>1254.45.12.7</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>1254.45.12.8</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>1254.45.12.9</keycode>
> 	</row>
>
> 	<row>
> 		<level>40</level>
> 		<keycode>99.25.6</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>99.25.6.45</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>99.25.6.46</keycode>
> 	</row>
> </data>
>
> What could be the XPath expression to get the maximum number of nodes of
> level=50 in data those keycode starts like the level=40 line ?
> Here the answer would be 3 as the maximum number of level = 50 nodes for
> a given level = 40 is 3
> I have tried several things, but I am stuck....
> (I am using XSLT 2.0 on Saxon)
>
>
> Thanks for lending me some neurons...
> Best regards,
> Fabien

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