Subject: Re: [xsl] Need to process mixed content(text() and node()) in string matching From: "Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx> Date: Thu, 09 Dec 2010 10:10:22 +0100 |
With XSLT 2.0, you could first replace ':' with some empty element and then, in a second pass, group all node()s in the paragraph, starting each group with that newly introduced empty element.
On 09.12.2010 10:02, Mandar Jagtap wrote:Hi,
I have following scenario:
Source xml is:
<p>This is paragraph text..<b>and bold</b> and normal<i>and italic</i> with value: ParagraphValue.</p>
The XSLT should match the string (mixed with text() of<p>, content of element<i>,<b>) as " This is paragraph text..and bold and normal and italic with value" in<p> element and desired output given below.
<paragraph1>This is paragraph text..<b>and bold</b> and normal<i>and italic</i> with value</paragraph1> <paragraph2>ParagraphValue.</paragraph2>
I tried with following approach:
<xsl:template match="p"> <xsl:choose> <xsl:when test="contains(. , ':')"> <paragraph1><xsl:value-of select="substring-before(., ':')"/></paragraph1> <paragraph2><xsl:value-of select="substring-after(., ':')"/></paragraph2> </xsl:when> <xsl:otherwise><paragraph1><xsl:avlue-of select="."/></paragraph1></xsl:otherwise> </xsl:choose> </xsl:template>
But with I could get only string but not elements<b> and<i> alongwith its content.
Any suggestions on what would be best approach to achieve this?
Thanks in advance...
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