Re: [xsl] Re: Identity Transform with special grouping

Subject: Re: [xsl] Re: Identity Transform with special grouping
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sat, 05 Feb 2011 15:20:06 +0100
Senthilukvelaan wrote:
"sections" element is not showing up in my output. I do not know , how
could I include that in my xslt.


Sorry, I did not notice.
You need to write a template for the parent element of "section" elements then e.g.


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:param name="n" select="2"/>

<xsl:output method="xml" omit-xml-declaration="yes"  indent="yes"
encoding="UTF-8" />
<xsl:strip-space elements="*"/>

<xsl:template match="node() | @*">
  <xsl:copy>
    <xsl:apply-templates select="node()| @*"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="*[section]">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="section[1]/preceding-sibling::node()"/>
<sections>
<xsl:apply-templates select="section[position() &lt; $n]"/>
</sections>
<xsl:apply-templates select="section[last()]/following-sibling::node()"/>
</xsl:copy>
</xsl:template>


</xsl:stylesheet>




--


	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/

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