Subject: [xsl] I thought i knew how to do this -- followup From: russurquhart1@xxxxxxxxxxx Date: Wed, 23 Feb 2011 16:06:32 -0600 (CST) |
I wanted to thanked everyone who replied. Special thanks to Wendell for patience as i ride my short little school bus of xsl! :) I want to post my follow up source that appears to work, but also point out an anomaly, to me at least. The code is as follows: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()" /> </xsl:copy> </xsl:template> <xsl:template match="*[@filter]"> <xsl:choose> <!-- <xsl:when test="contains(@filter, 'filter10') or contains(@filter, 'filter1')">--> <xsl:when test="contains(@filter, 'filter10') or (./@filter='filter1' and not(contains(@filter, 'filter17')))"> <xsl:copy> <xsl:apply-templates select="@*|node()" /> </xsl:copy> </xsl:when> <xsl:otherwise /> </xsl:choose> </xsl:template> </xsl:stylesheet> (A little update. A filter value of 'filter1' will ONLY appear by itself and NOT in a string with other values, as i reported yesterday.) With that said i felt sure that i could THEN test for the 'filter1' value by using a @filter='filter1' type of check. (Thinking the '=' would be a complete, exact type of comparison as opposed to a 'contains' function call. When i ran the xsl, i did have some @filter='filter17' values, BUT these got matched by my @filter='filter1' check. (I know because i took that conditional out and no 'filter17' values were output.) Is this correct? To summarize. I thought: ./@filter='filter1' would NOT match @filter='filter17' but fully expected contains(. , 'filter1') to match @filter='filter17'. When someone get time, no hurry, could they explain this anomaly to me? Thanks, Russ
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