Subject: RE: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0 From: Robby Pelssers <Robby.Pelssers@xxxxxxx> Date: Wed, 6 Jul 2011 20:58:13 +0200 |
http://www.w3.org/TR/xpath-functions/#func-deep-equal -----Original Message----- From: Robby Pelssers [mailto:Robby.Pelssers@xxxxxxx] Sent: Wednesday, July 06, 2011 8:57 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0 Try the deep-equal function... Robby -----Original Message----- From: Wolfhart Totschnig [mailto:wolfhart@xxxxxxxxxxxxx] Sent: Wednesday, July 06, 2011 8:55 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0 Hello, I have a seemingly simple xslt problem to which I cannot find the solution. I want to test whether the context node, which is an <author> element with the form (first?, middle?, last), is equal to one of a set of <person> elements. By "equal" I mean having the same child elements and values of these elements. At first, I thought it would be as easy as test="path/person = ." But then I realized that the "=" operator compares the string values of the nodes, such that <author> <first>John</first> <last>Doe</last> </author> and <person> <last>JohnDoe<last> </person> will be evaluated as equal, which I want to avoid. So how can I check, in XSLT 1.0, whether two nodes are equal in the sense I intend? Thank you for your help! Wolfhart
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