Re: [xsl] redirecting ouput to a different file?

[Dan Vint <dvint@xxxxxxxxx>]

thanks

Given that I have the mapping file I should be able to use it as the 
list of documents to process as you suggest, which would give me 
additional control and options within kernow.

..dan

At 01:56 AM 8/19/2011, you wrote:
> > Using Kernow I can easily run this stylesheet against a directory and it
> > will recreate the same filename with the changed content. That gets me
> > halfway there.
> >
> > The question here is, can I read file of one name and output all this
> > result to a new file name based upon the values in the mapping file?
>
> You can do:
>
> <xsl:template match="/">
>   <xsl:variable name="output-filename" select=" construct the 
> filename here "/>
>   <xsl:result-document href="/path/to/output/{$output-filename}">
>
> ...which will give you control over the output filename.  The default
> output file will probably still be created, so you would need to take
> that into consideration with the output file path.
>
> Alternatively, move from the 'directory' tab to the 'standalone' tab,
> change your transform to pull in the source xml itself:
>
> <xsl:template name="main">
>   <xsl:for-each select="collection(...)">
>     <xsl:variable name="output-filename" select=" construct the
> filename here "/>
>     <xsl:result-document href="/path/to/output/{$output-filename}">
>
>
>
>
> --
> Andrew Welch
> http://andrewjwelch.com

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Danny Vint

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