Re: [xsl] __LINE__ equivalent in XSLT

[Michael Kay <mike@xxxxxxxxxxxx>]

On 02/12/2011 15:01, Bartolomeo Nicolotti wrote:
> hello,
>
> I've tried this:
>
> zxsl:value-of select="saxon:line-number(.)"/>
> </xsl:template>
>
> buy gives me the line of the input xml

My suggestion was that you should write an XSLT stylesheet that 
preprocesses the stylesheet: so that at this time, the stylesheet IS the 
input XML. That mirrors the way the C preprocessor handles it.

saxon:line-number also requires a version of Saxon that supports it 
(e.g. Saxon-PE 9.3) and setting the -l option on the command line so 
that line numbers are maintained.

Michael Kay
Saxonica
> I need to know the line number in the xslt itself
>
> Many thanks
>
> Bye
>
> Il giorno ven, 02/12/2011 alle 13.01 +0000, Michael Kay ha scritto:
> > You could implement the preprocessor easily enough if you are using
> > Saxon. For example if you use<?line?>  then you can write the
> > preprocessor as
> >
> > <xsl:template match="*">
> >     .. identity template ..
> > </xsl:template>
> >
> > <xsl:template match="processing-instruction(line)">
> > <xsl:value-of select="saxon:line-number(.)"/>
> > </xsl:template>
> >
> > Michael Kay
> > Saxonica
> >
> > On 02/12/2011 12:14, Bartolomeo Nicolotti wrote:
> > > To whom it may concern,
> > >
> > > in C there's a pre-processor directive
> > >
> > > __LINE__
> > >
> > > that gives you the line of source where the directive is.
> > >
> > > Is there an equivalent in XSLT?
> > >
> > > Many thanks
> > >
> > > Best regards
> > >
> > > Bartolomeo