Re: [xsl] __LINE__ equivalent in XSLT

[Bartolomeo Nicolotti <bnicolotti@xxxxxxxxx>]

Hello,

it may be also 5min, but if you're 20h late and still 10h do work you
don't have time, also it's quite a delicate task to change an xslt with
another xslt, so I don't want to do it in an hurry, even if a nice
idea...

Maybe in the future...

Many thanks

Bye

Il giorno ven, 02/12/2011 alle 17.18 +0100, Bartolomeo Nicolotti ha
scritto:
> Hello,
> 
> ok, now I've understood, but a little bit long task for my schedule...
> 
> maybe some time in the future...
> 
> Many thanks
> 
> bye
> 
> 
> Il giorno ven, 02/12/2011 alle 17.16 +0100, Wolfgang Laun ha scritto:
> > Michael suggested the implementation of an equivalent of a C preprocessor
> > by replacing processing instructions *in your XSLT" by *another XSLT* which
> > transforms the input XML (your actual XSLT) into one where "<?line?> is
> > replaced by the current line number within that XML (your actual XSLT).
> > 
> > -W
> > 
> > On 2 December 2011 16:02, Bartolomeo Nicolotti <bnicolotti@xxxxxxxxx> wrote:
> > > Sorry,
> > >
> > > this
> > >
> > > (line 34)<xsl:comment>line <xsl:value-of  select="saxon:line-number()"/>
> > >
> > > gives this
> > >
> > > <!--line -1
> > >
> > > Many thanks
> > >
> > > Bye
> > >
> > > Il giorno ven, 02/12/2011 alle 16.01 +0100, Bartolomeo Nicolotti ha
> > > scritto:
> > >> hello,
> > >>
> > >> I've tried this:
> > >>
> > >> zxsl:value-of select="saxon:line-number(.)"/>
> > >> </xsl:template>
> > >>
> > >> buy gives me the line of the input xml
> > >>
> > >> I need to know the line number in the xslt itself
> > >>
> > >> Many thanks
> > >>
> > >> Bye
> > >>
> > >> Il giorno ven, 02/12/2011 alle 13.01 +0000, Michael Kay ha scritto:
> > >> > You could implement the preprocessor easily enough if you are using
> > >> > Saxon. For example if you use <?line?> then you can write the
> > >> > preprocessor as
> > >> >
> > >> > <xsl:template match="*">
> > >> >    .. identity template ..
> > >> > </xsl:template>
> > >> >
> > >> > <xsl:template match="processing-instruction(line)">
> > >> > <xsl:value-of select="saxon:line-number(.)"/>
> > >> > </xsl:template>
> > >> >
> > >> > Michael Kay
> > >> > Saxonica
> > >> >
> > >> > On 02/12/2011 12:14, Bartolomeo Nicolotti wrote:
> > >> > > To whom it may concern,
> > >> > >
> > >> > > in C there's a pre-processor directive
> > >> > >
> > >> > > __LINE__
> > >> > >
> > >> > > that gives you the line of source where the directive is.
> > >> > >
> > >> > > Is there an equivalent in XSLT?
> > >> > >
> > >> > > Many thanks
> > >> > >
> > >> > > Best regards
> > >> > >
> > >> > > Bartolomeo