Re: [xsl] read array

[henry human <henry_human@xxxxxxxx>]

Hi
The XML

 <?xml version="1.0"?>
<root>
<Invoice>
<DocumentReference>
<ID>100</ID>
</DocumentReference>
</Invoice>
<Invoice>
<DocumentReference>
<ID>200</ID>
</DocumentReference>
</Invoice>
</root>

  Output should be:
1.100_2.200 

best regards


----- Urspr|ngliche Message -----
Von: Andrew
Welch <andrew.j.welch@xxxxxxxxx>
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Cc:
Gesendet: 11:38 Mittwoch, 21.Dezember 2011
Betreff: Re: [xsl] read array

On
21 December 2011 10:33, henry human <henry_human@xxxxxxxx> wrote:
> Ther are
two elements "ID" in the xml
> I will read them and concat together:
>
<xsl:for-each select="root/Invoice/DocumentReference/ID">
> ...........
>
</xsl:for-each>
> Concat([1].ID + [2].ID

There are many ways... you need to
re-post with an example and the
required output.



-- 
Andrew Welch
http://andrewjwelch.com