Re: [xsl] format string with leading zeros

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2012-01-04 15:46 +0000, henry human wrote:
>   Hi I have following scenario, the itemCode field  must be 14 
> digits lang. I try to ignore the last two decimals of the itemCode 
> field if the itemCode is more than 14 digits long (16 digits). And 
> if the itemCode has less than 14,  fill field with leading zeros so 
> that the itemCodeCode is still 14 digits long.   Input Example(1): 
> itemCode : 0.0123456789 output itemCode: 000.0123456789   Input 
> Example(2): itemCode : 0.01111123456789 output itemCode: 
> 0.011111234567 Thanks you

Does the following help?  It uses two steps to first trim and then 
pad the input to produce the output.

. . . . . . . . . Ken

~/t/ftemp $ xslt2 henry.xsl henry.xsl
<?xml version="1.0" encoding="UTF-8"?>
000.0123456789
0.011111234567
~/t/ftemp $ cat henry.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  xmlns:my="urn:X-Henry" exclude-result-prefixes="my"
  version="2.0">

<xsl:template match="/">
  <xsl:text>&#xa;</xsl:text>
  <xsl:value-of select="my:trim('0.0123456789')"/>
  <xsl:text>&#xa;</xsl:text>
  <xsl:value-of select="my:trim('0.01111123456789')"/>
  <xsl:text>&#xa;</xsl:text>
</xsl:template>

<xsl:function name="my:trim">
  <xsl:param name="str"/>
  <xsl:variable name="temp"
                select="concat('00000000000000',substring($str,1,14))"/>
  <xsl:sequence select="substring($temp,string-length($temp)-13)"/>
</xsl:function>

</xsl:stylesheet>
~/t/ftemp $


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