Re: [xsl] how to achieve this ?

[Boudewijn Bosgoed <bbosgoed@xxxxxxx>]

Op 23 jan 2012, om 08:26 heeft Roelof Wobben het volgende geschreven:

Not knowing how the input looks like, i would say that:
<ul class="menu" id={concat('menu', @value)}>

should do it for you, its a short notation for xsl:value-of select
 

> For a menu I have to take care that every <menu class> get a unique id.
> 
> I thought this would work : 
> 
> <xsl:template match="year">
> <ul class="menu" id= "concat ('menu', @value)" >
>    <li>
>    <a href="#"> <xsl:value-of select="@value"/> </a>
>      <ul class="acitem">
>             <xsl:apply-templates select="month" />
>      </ul>
>     </li>
> </ul>
> </xsl:template>
> 
> But it don't work.
> 
> Do I have to use here <xsl:value-of> or is there a better way ?