Subject: Re: [xsl] how to achieve this ? From: Boudewijn Bosgoed <bbosgoed@xxxxxxx> Date: Mon, 23 Jan 2012 08:35:36 +0100 |
Op 23 jan 2012, om 08:26 heeft Roelof Wobben het volgende geschreven: Not knowing how the input looks like, i would say that: <ul class="menu" id={concat('menu', @value)}> should do it for you, its a short notation for xsl:value-of select > For a menu I have to take care that every <menu class> get a unique id. > > I thought this would work : > > <xsl:template match="year"> > <ul class="menu" id= "concat ('menu', @value)" > > <li> > <a href="#"> <xsl:value-of select="@value"/> </a> > <ul class="acitem"> > <xsl:apply-templates select="month" /> > </ul> > </li> > </ul> > </xsl:template> > > But it don't work. > > Do I have to use here <xsl:value-of> or is there a better way ?
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