Re: [xsl] collection issue, update/rename file

[Andrew Welch <andrew.j.welch@xxxxxxxxx>]

On 29 February 2012 11:02,  <davep@xxxxxxxxxxxxx> wrote:
> input a directory full of .xml files
>
> running a transform to modify one element, identity
> transform for the rest.
>
> (Yes, I have created a backup)
>
> I want to
> process A.xml, write out A.xml ... somehow
> (no I'm not on Linux to make it easy)
>
> I'm using
>  <xsl:for-each select="collection('file:///Long-path?select=*.xml')">
>  <xsl:result-document
>        href="???"
>        method="xml"
>        encoding="utf-8"
>       indent="yes">
>
>        <xsl:apply-templates/>
>
>
> base-uri(.) returns the full pathname of the source document?
> Do I have to work with that to obtain A.xml?
>  (text processing....)
> Is there some way I can obtain the filename.extn?

1. use Kernow :)

or

2. use tokenize(document-uri(.), '/')[last()]


--
Andrew Welch
http://andrewjwelch.com