Subject: Re: [xsl] shortest way to write this xsl:if statement From: Wolfgang Laun <wolfgang.laun@xxxxxxxxx> Date: Fri, 15 Jun 2012 15:17:09 +0200 |
Sorry, I meant to indicate that this should produce all the nodes that should be processed by the loop, <xsl:for-each select="...."> On 15/06/2012, Wolfgang Laun <wolfgang.laun@xxxxxxxxx> wrote: > You might need an XPath expression > test="D4/G10/(X,Y,Z)[. = ('A','B','C','D')]" > -W > > > On 15/06/2012, henry human <henry_human@xxxxxxxx> wrote: >> Now the problem is, the loop bellow of xsl:if is only one time created but >> I >> have more findings in the if statement >> regarding A, B, C, D (founds at least 4 times because D4/G100/6id = 'A' , >> D4/G100/9id = 'B' , D4/G100/10id = 'C' , D4/G100/11id ='D') >> => the code bellow of the xsl:if statemnt should be repeated as much as >> if >> statement find A, B, C, D,.. >> >> >> >> >> ----- Urspr|ngliche Message ----- >> Von: G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> >> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx; "xsl-list@xxxxxxxxxxxxxxxxxxxxxx" >> <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> >> CC: >> Gesendet: 13:59 Freitag, 15.Juni 2012 >> Betreff: Re: [xsl] shortest way to write this xsl:if statement >> >> >> At 2012-06-15 12:54 +0100, henry human wrote: >>> Hello >>> The following if statement is too long if try it as in the sample >>> bellow. >>> How could be shorter? >>> The if - logic to create a for-each loop: >>> ---------------- >>> xsl:if >>> D4/G100/6id or D4/G100/9id or D4/G100/12id or D4/G100/6id15 or >>> D4/G100/45id or D4/G100/22id, D4/G100/10id >>> or D4/G100/19id is 'A' or 'B' or 'C', or 'D' or 'F' >>> >>> The Sample: >>> <xsl:if test="D4/G100/6id = 'A' OR test="D4/G100/6id = 'B' OR >>> test="D4/G100/6id = 'C' OR test="D4/G100/9id = 'A' OR test="D4/G100/9id >>> = >>> 'B' .....> >>> >>> <xsl:for-each select=" ......"> >>> ... >>> </xsl:for-each> >>> >>> </xsl:if> >> >> Element names cannot begin with digits, so I'm unclear how you are going >> to >> be testing elements such as <6id>. >> >> But, assuming you had elements D4/G100/X and D4/G100/Y and D4/G100/Z, you >> could have in XSLT2 the following: >> >> <xsl:if test="D4/G100/(X,Y,Z) = ('A','B','C')"> >> >> ... which is equivalent to: >> >> D4/G100/X = 'A' or >> D4/G100/X = 'B' or >> D4/G100/X = 'C' or >> D4/G100/Y = 'A' or >> D4/G100/Y = 'B' or >> D4/G100/Y = 'C' or >> D4/G100/Z = 'A' or >> D4/G100/Z = 'B' or >> D4/G100/Z = 'C' >> >> When using the "=" comparison operator, either operand can be a set. The >> processor walks through the comparisons in an arbitrary order eventually >> testing each of the left operand with each of the right operand and stops >> when it hits a true() result and returns true(). If you get a false() >> returned, you know the processor has checked every possible combination >> and >> every combination has returned false(). >> >> I hope this helps. >> >> . . . . . . . . . . . Ken >> >> -- >> Public XSLT, XSL-FO, UBL and code list classes in Europe -- Oct 2012 >> Contact us for world-wide XML consulting and instructor-led training >> Free 5-hour lecture: http://www.CraneSoftwrights.com/links/udemy.htm >> Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ >> G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx >> Google+ profile: https://plus.google.com/116832879756988317389/about >> Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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