[xsl] finding the position of a node within a node set

Subject: [xsl] finding the position of a node within a node set
From: Wolfhart Totschnig <wolfhart@xxxxxxxxxxxxx>
Date: Sun, 26 Aug 2012 00:41:55 -0500
Dear list,

I have an XPath question to which I cannot find the answer.

Let $node_set be a set of element nodes, stored in a variable. In this set there is an element with @id="foo". I would like to know the position of this element within the node set. I found the following solution:

<xsl:for-each select="$node_set">
<xsl:if test="@id='foo'">
<xsl:value-of select="position()">
</xsl:if>
</xsl:for-each>

I cannot but think that there is a quicker, XPath-only solution to this, yet I cannot find it. Thank you for your help!

Wolfhart

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