Re: [xsl] Template for node-set parents

[Michael Kay <mike@xxxxxxxxxxxx>]

My solution assumed XSLT 2.0. I think that these days, if you want to 
use XSLT 1.0, you should say so - it's been superseded for nearly 6 
years now.

I'm afraid I don't do 1.0 solutions for people - my memories of how to 
get round its restrictions are fading rapidly. But there are probably 
other people on the list who can help.

Michael Kay
Saxonica

On 01/11/2012 21:14, Darren Oh wrote:
> Thanks for the suggestion. I got stuck when trying to produce a sorted node-set. Instead of a node-set, I got a result tree fragment, for which no node-set operations are possible. Here is a simplified example to illustrate the problem. Whereas it is possible to select a node from $result, it is not possible to select a node from $sorted. Any ideas?
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
>    <xsl:output method="xml"/>
>    <xsl:template match="*">
>      <xsl:copy>
>        <xsl:apply-templates/>
>      </xsl:copy>
>    </xsl:template>
>    <xsl:variable name="result" select="/response/data/result"/>
>    <xsl:variable name="sorted">
>      <xsl:apply-templates select="/response/data/result">
>        <xsl:sort select="COMPANY_SORT" data-type="text" order="descending"/>
>      </xsl:apply-templates>
>    </xsl:variable>
>    <xsl:template match="/">
>      <xsl:copy-of select="$result[1]"/>
>      <xsl:copy-of select="$sorted[1]"/>
>    </xsl:template>
> </xsl:stylesheet>
>
> On Oct 19, 2012, at 1:27 PM, Michael Kay wrote:
>
> > Try:
> >
> > 1. define a global variable $v1 that selects the result of the path expression in document order.
> >
> > 2. define another global variable $v2 that selects the sorted result of the path expression
> >
> > 3. Use a base template rule that's the identity copy
> >
> > 4. Add a template rule that matches nodes in $v1 (match="node()[. intersect $v1]). In this rule, determine the index position of this node in $v1 (count ($v1[. << $this]) + 1), and output the corresponding node from $v2 (copy-of select="$v2[$n]").
> >
> > Michael Kay
> > Saxonica
> >
> >
> > On 19/10/2012 18:03, Darren Oh wrote:
> > > I am trying to generate a stylesheet that copies an XML source document. The only change should be that nodes selected by an XPath expression are sorted. I want this to work for any XML source document. The only information available to generate the stylesheet is the XPath expression and the sort criteria. I think this requires creating a template for the parents of the nodes selected by the XPath expression. How can I do this?