Subject: Re: [xsl] An XPath expression which checks that no two websites have the same username From: Wolfgang Laun <wolfgang.laun@xxxxxxxxx> Date: Mon, 5 Nov 2012 11:54:37 +0100 |
Perhaps comparing the count of all @to values with the count of the union of all @to values: count(map/*/@to) eq count(union(map/*/@to)) which assumes, of course, that you don't have full identical duplicates. -W On 05/11/2012, Costello, Roger L. <costello@xxxxxxxxx> wrote: > Hi Folks, > > I need a good XPath expression which checks that no two websites have the > same username. > > Here is a map between websites and usernames: > > <map> > <singletonMap from="Amazon" to="BasketballKing" /> > <singletonMap from="Apple" to="RandomGamer" /> > <singletonMap from="Ebay" to="CornFoo" /> > <singletonMap from="Google" to="LatenightRevolution" /> > <singletonMap from="Microsoft" to="OldTrue" /> > <singletonMap from="VirginAtlantic" to="TheSinger" /> > </map> > > In that example no two websites have the same username. > > I created an XPath expression which does the job, but I suspect there is a > simpler expression. Here is my attempt: > > empty(for $i in map/*/@to return map/*[@to eq $i][2]) > > Would you provide a simpler (more efficient, more elegant) version please? > > /Roger
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] An XPath expression which che, Costello, Roger L. | Thread | Re: [xsl] An XPath expression which, G. Ken Holman |
[xsl] An XPath expression which che, Costello, Roger L. | Date | Re: [xsl] An XPath expression which, G. Ken Holman |
Month |