Subject: Re: [xsl] deep copy without attributes From: Ihe Onwuka <ihe.onwuka@xxxxxxxxx> Date: Tue, 21 May 2013 01:35:54 +0100 |
On Tue, May 21, 2013 at 12:02 AM, Graydon <graydon@xxxxxxxxx> wrote: > On Mon, May 20, 2013 at 10:34:31PM +0100, Ihe Onwuka scripsit: >> On Mon, May 20, 2013 at 8:48 PM, Graydon <graydon@xxxxxxxxx> wrote: >> > You can't make the solution simpler than the problem. >> >> But you can make the solution more complicated than the problem. >> >> Say I wanted to copy a directory structure but not carry over the >> symbolic links. >> >> I'd expect to be able to accomplish that by setting an option on my >> copy command rather than having to implement a recursive shell script. > > Symbolic links, in XML terms, would be elements from some other tree > inserted by reference. XML doesn't do that, and if it did do that, > there'd be a case for some kind of "is it really there, or referenced?" > distinction. (Attributes, by file system analogy, would be things like > mtime and ctime.) > it's not hard to find another example (try hidden files) - should I be forced to write a recursive shell depending on whether I want to exclude or include them in the copy? > > <xsl:template match="node()"> > <xsl:copy> > <xsl:apply-templates select="node()"/> > </xsl:copy> > </xsl:template> > > does that; it's not recursive, it's a single template. It'll get > applied to all the nodes, but that's the magic of the XSLT declarative f> if it were only about whether cognoscenti can think up an elegant solution - we'd still all be doing Muenchian Grouping. I've not been paying attention to 3.0 but I'd be looking at copy-of and thinking it is ripe for accepting an anonymous function/template that is applied as it traverses it's hierarchy. which would be another way of addressing the issue.
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