Subject: Re: [xsl] Show all permutations of N coins ... without using recursion? From: David Carlisle <davidc@xxxxxxxxx> Date: Sun, 01 Sep 2013 11:41:43 +0100 |
Jacob Mal} wrote:
You just iterate from 1 to 2^N, each step gives you one output sequence, you just have to convert it to the desired format.
Thank you very much!
I did as you suggested and it works great.
The below stylesheet shows the permutations of N coins, implemented in two ways: (1) using recursion, and (2) using iteration.
By the way, I recently learned about the xsl:iterate instruction. Wow! Such a useful instruction. How have I lived without it all these years.
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