Re: [xsl] Keys with duplicates should be simple

[Ihe Onwuka <ihe.onwuka@xxxxxxxxx>]

On Fri, Jan 31, 2014 at 7:28 PM, Ihe Onwuka <ihe.onwuka@xxxxxxxxx> wrote:
> On Fri, Jan 31, 2014 at 5:36 PM, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
>> On Fri, Jan 31, 2014 at 9:16 AM, Wendell Piez <wapiez@xxxxxxxxxxxxxxx> wrote:
>>> For this, one could also say
>>>
>>> a[@href = (../a except .)/@href]
>>
>>
>>
>> Hi Wendell,
>>
>> I agree with every statement in your message.
>>
>> At the same time, I believe, that the OP wouldn't have posted the
>> question in case he was allowed to use XSLT 2 -- as it is obvious that
>> in XSLT 2 one should use the <xsl:for-each-group> instruction.
>>
>> In the unlikely case that someone is using XSLT 2 and still trying to
>> use keys for grouping, this most probably means that such person isn't
>> aware of the existence of the <xsl:for-each-group> instruction.
>>
>
> http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201211/msg00170.html
>

Oh Wendell and just for bonus that the same thread that articulates
what I hate about except.


> OP is using XSLT 2. OP only wants to find what things have duplicates.
> Thats not a grouping problem, it's a problem that a certain variant of
> for-each-group happens to solve but it's not the simplest way of
> solving it.