Subject: Re: [xsl] How to show explicitly the implicit sequence constructor? From: John Lumley <john@xxxxxxxxxxxx> Date: Sat, 29 Mar 2014 09:58:15 +0000 |
> On 29 Mar 2014, at 09:28, "Costello, Roger L." <costello@xxxxxxxxx> wrote > > For example, this would be a neat way to explicitly show the sequence constructor: > > <xsl:template match="Book"> > <xsl:sequence> > <xsl:value-of select="Title" /> > <xsl:value-of select="Author" /> > </xsl:sequence> > </xsl:template> > > Unfortunately that is not legal. > > Is there a way to explicitly show the sequence constructor? My reading of the 3.0 Working Draft suggests that that construct should be legal - <xsl:sequence> can contain a sequence constructor if no @select. Of course you could indicate the sequence constructor inside the <xsl:sequence> with another <xsl:sequence> ...... ;-) John
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