Re: [xsl] Removing <div/> tags from HTML

You're making it harder than it needs to be.

Just use an identity transform that has a template for <div> like:

<xsl:template match="div">
  <xsl:apply-templates/>
</xsl:template>

That will filter out the <div> elements but leave their contents.

Cheers,

E.
bbbbb
Eliot Kimber, Owner
Contrext, LLC
http://contrext.com




On 5/19/14, 3:23 PM, "Mark Peters markpeters.work@xxxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>Hi,
>
>
>I'm trying to convert documentation from HTML to another markup language.
>The documentation includes content nested in many various levels of
><div/> tags.
>
>For example:
>
><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
>"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
>
><html xmlns="http://www.w3.org/1999/xhtml";>
>    <head>
>        <title>Title</title>
>    </head>
>    <body>
>        <h1>Title</h1>
>
>        <div>
>            <div>
>                    <p>Text</p>
>                        <div>
>                            <ul>
>                                <li>List item</li>
>
>                                <li>List item</li>
>                                <li>List item</li>
>                            </ul>
>                        </div>
>                    <p>Text</p>
>
>                    <h2Title</h2>
>                    <h3>Title</h3>
>                    <p>Text.</p>
>                    <div>
>                        <div>
>                            <p>Text</p>
>
>                         <div>
>                    <div>
>               <div>
>            <div>
>
>     </body>
>
></html>
>
>
>I simply want to remove all <div/> tags but retain the child nodes and
>attributes for each. I'm also removing the <html/> nodes but retaining
>the children, and removing the <head/> node altogether. But I can figure
>out how to accomplish those goals.
>
>
>The desired output would look like this:
>
>    <body>
>        <h1>Title</h1>
>         <p>Text</p>
>         <ul>
>              <li>List item</li>
>
>              <li>List item</li>
>              <li>List item</li>
>          </ul>
>          <p>Text</p>
>          <h2Title</h2>
>           <h3>Title</h3>
>
>           <p>Text.</p>
>            <p>Text</p>
>     </body>
>
>
>Here's current stylesheet. I've tried to remove the <div/> tags several
>different ways, using identity templates and for-each elements.
>
><?xml version="1.0" encoding="UTF-8"?>
><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>version="2.0" xmlns="http://www.w3.org/1999/xhtml";
>xpath-default-namespace="http://www.w3.org/1999/xhtml";>
>
>    <xsl:output method="xml" indent="no" omit-xml-declaration="yes"
>encoding="UTF-8"/>
>
>    <xsl:template match="/*">
>        <xsl:apply-templates select="node()"/>
>
>    </xsl:template>
>
>    <xsl:template match="head"/>
>    <xsl:template match="@*|node()">
>        <xsl:copy>
>            <xsl:apply-templates select="@*|node()"/>
>
>        </xsl:copy>
>    </xsl:template>
>
>    <xsl:template match="body">
>        <xsl:element name="body">
>            <xsl:for-each select="//node()">
>
>                <xsl:choose>
>                    <xsl:when test="self::div">
>                        <xsl:apply-templates select="node()"/>
>                    </xsl:when>
>
>                    <xsl:otherwise>
>                        <xsl:apply-templates
>select="self::node()|node()"/>
>                    </xsl:otherwise>
>                </xsl:choose>
>
>            </xsl:for-each>
>        </xsl:element>
>    </xsl:template>
>
></xsl:stylesheet>
>
>
>With this current stylesheet, I wanted to test each child node under
><body/>. For each <div/> node, the stylesheet would copy the child nodes
>and attributes only. For all other nodes, the stylesheet would copy the
>current node and all children. But my output is blank.
>
>
>Thanks in advance for any help.
>
>
>Mark
>
>
>
>
>
>
>
>
>XSL-List info and archive
><http://www.mulberrytech.com/xsl/xsl-list>EasyUnsubscribe
><-list/1278982>
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