Re: [xsl] Re: Can the default function namespace be undeclared in XSLT?

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On Sun, Jun 1, 2014 at 3:06 PM, Michael Kay mike@xxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> In XSLT the default function namespace is always the "fn" namespace; this cannot be changed.

Thank you.

Is it correct to conclude that due to this, an instance of a
user-defined type that is in no-namespace  can only be constructed
using casting, but not using the name of the type as a constructor
function?


-- 
Cheers,
Dimitre Novatchev
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