Subject: Re: [xsl] Sorting a sequence and selecting the first element after sort From: "Jorge . chocolate.camera@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 8 May 2015 11:50:38 -0000 |
I now see that, on top of that, I am adding duplicate copies of nodes that match both conditions to the sequence (-_-;). I would also appreciate a hint on how to make that selection without dupes. On Fri, May 8, 2015 at 1:44 PM, Jorge . chocolate.camera@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > I'd like to select the first child of the current node that either: > > 1. is a "foo" element > 2. has "foo" or "bar" descendant(s) > > The following sequence returns me all nodes matching either or both of > those conditions: > > <xsl:sequence select="foo, *[descendant::foo, descendant::bar]"/> > > but not necessarily ordered according to their position as children of > the current node. As a result, the first element in that sequence, > selected like this: > > <xsl:sequence select="(foo, *[descendant::foo, descendant::bar])[1]"/> > > is not necessarily the first matching child of the current node. > > How do I sort elements in that sequence according to their position as > children of the current context, so that the first element in that > sequence is actually the first matching child in the current node?
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