Subject: Re: [xsl] Document reordering after applying path expression From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 30 Jun 2015 21:30:59 -0000 |
The result of an expression that uses the b/b operator is sorted into document order. Document order among nodes in separate trees is implementation-dependent, so $a may come either before or after $b depending on the implementation. Michael Kay Saxonica > On 30 Jun 2015, at 20:20, Max Toro maxtoroq@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > The following stylesheet: > > <?xml version="1.0" encoding="utf-8"?> > <xsl:stylesheet version="2.0" exclude-result-prefixes="#all" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:xs="http://www.w3.org/2001/XMLSchema"> > > <xsl:output method="xml" indent="yes"/> > > <xsl:template name="main"> > > <xsl:variable name="a"> > <a/> > </xsl:variable> > > <xsl:variable name="b"> > <b/> > </xsl:variable> > > <for-each1> > <xsl:for-each select="reverse(($a, $b))"> > <xsl:copy-of select="."/> > </xsl:for-each> > </for-each1> > > <for-each2> > <xsl:for-each select="reverse(($a, $b))/*"> > <xsl:copy-of select="."/> > </xsl:for-each> > </for-each2> > > </xsl:template> > > </xsl:stylesheet> > > Outputs: > > <?xml version="1.0" encoding="UTF-8"?> > <for-each1> > <b/> > <a/> > </for-each1> > <for-each2> > <a/> > <b/> > </for-each2> > > Why is the sequence reordered after applying a path expression? > Is this conformant with the standard? If yes, what section talks about it? > > I'm using Saxon 9.6.0.6. > > Original post: http://stackoverflow.com/questions/31126950 > > -- > Max Toro
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