Subject: Re: [xsl] CALS to XHTML table - rowspan From: "Bob Thomas bob.thomas@xxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 5 Oct 2015 15:52:57 -0000 |
Before you begin transforming make sure that you are starting from CALS tables that work. Your sample CALS table has problems. I am guessing that you meant something closer to this: <table> <tgroup cols="3"> <tbody> <row> <entry morerows="2">r1c1</entry> <entry morerows="1">r1c2</entry> <entry>r1c3</entry> </row> <row> <entry>r2c3</entry> </row> <row> <entry>r3c2</entry> <entry>r3c3</entry> </row> <row> <entry>r4c1</entry> <entry>r4c2</entry> <entry>r4c3</entry> </row> </tbody> </tgroup> </table> Best Regards, Bob Thomas Tagsmiths, LLC On Mon, Oct 5, 2015 at 9:39 AM, a kusa akusa8@xxxxxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > Hello: > > It has been a while since I worked on XSLT. But I have a current issue > that I need to solve with xslt. > > I have a CALS table that has @morerows. I have to generate a table > that does not have a rowspan attribute, and generate cells according > to the value of @morerows. > > So, my input XML looks like this: > > <table> > <tgroup> > <tbody> > <row><entry morerows="2">test 1</entry> > <entry morerows="1">test 2</entry> > <entry morerows="0">test 3</entry> > </row> > <row><entry morerows="0">test 4</entry> > <entry morerows="1">test 5</entry> > <entry morerows="0">test 6</entry> > </row> > </tbody> > </tgroup> > </table> > > How do I generate rows/cells based on morerows in xslt? > > Any tips is appreciated. > > -- Bob Thomas +1 720 201 8260 Skype: bob.thomas.colorado Instant messaging: Gmail chat (bob.thomas@xxxxxxxxxxxxx) or Skype Time zone: Mountain (GMT-7)
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