Re: [xsl] Need Math Help: How to Convert Proportional Column Widths to Real Values?

["a kusa akusa8@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Thank you for all your input. It gets tricky without the total width.

Michael, just dumb doubt / clarification. For RestRW, is 'Total',
SumRW+SumAW?



On Wed, Dec 30, 2015 at 11:24 AM, Michael MC<ller-Hillebrand
mmh@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>> I was looking to do something similar and found this question. In my
>> case, I don't have the total table column width always. So, if I have
>> a mixed col width values of 1.38,1.38.1*,1.38, how can I find the real
>> value for 1*?
>
> As Eliot mentioned, some absolute total value is required. Unless you are
e.g. in an FO environment, where 100% can be seen as the current available
width.
>
> In a more general way I did it something like this:
>
> * Columns without width or just "*" are treated as "1*"
> * Calculate the sum of all relative widths (SumRW)
> * Calculate the sum of all absolute widths (SumAW)
>
> * Calculate remaining width RestRW := Total - SumAW
>   - If it is b	$ 0 we have a problem
>   - Else each remaining column width is ColRW / SumRW multiplied with the
RestRW
>
> - Michael