Re: [xsl] for-each-group - only get elements in each group

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Rick Quatro rick@xxxxxxxxxxxxxx wrote:

> <Cases>
>    <Story>
>      <Category>Category1</Category>
>      <Case>Case1</Case>
>      <Category>Category1</Category>
>      <Case>Case2</Case>
>      <Category>Category1</Category>
>      <Case>Case3</Case>
>      <Category>Category1</Category>
>      <Case>Case4</Case>
>      <Category>Category2</Category>
>      <Case>Case5</Case>
>      <Category>Category2</Category>
>      <Case>Case6</Case>
>      <Category>Category2</Category>
>      <Case>Case7</Case>
>      <Category>Category2</Category>
>      <Case>Case8</Case>
>    </Story>
> </Cases>

Here you have only one "Story" element with several "Category" and 
"Case" child elements.

> I want to group on each unique <Category> element and then only include the
> <Case> elements for each <Category>.

How do you relate a "Case" to a "Category"? Because they are direct 
siblings?


>      <xsl:template match="Cases">
>          <xsl:for-each-group select="Story" group-by="Category">
>              <category><xsl:copy-of
> select="current-grouping-key()"/></category>
>              <xsl:apply-templates select="Case"/>
>          </xsl:for-each-group>

You group the single "Story" by the "Category" child and then 
apply-templates to all "Case" child of the "Story".