Subject: [xsl] How to copy attribute value to text? From: "Kenneth Reid Beesley krbeesley@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 7 Jul 2016 05:22:26 -0000 |
If I start with an input XML document that contains mixed text with <word> elements like this: b& this is just <word correction=btoob>to</word> funny Ibd like to write an XSLT stylesheet that yields as output b& this is just <word origerror=btob>too</word> funny So in the output I effectively want (in the same <word> element) to 1. Set the value of a new attribute to the original text() value, and 2. Reset the text() value to be the value of the original @correction attribute Ibve tried many variants of the following, so far without success. Ibm using SaxonHE9-7-0-6J; it runs, but the results are not as expected/hoped. <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="word[@correction]"> <xsl:variable name="origtext" select="."/> <xsl:variable name="correction"> <xsl:value-of select="@correction"/> </xsl:variable> <xsl:copy> <xsl:copy-of select="@*[name()!='correction']"/> <xsl:attribute name="origerror" select="$origtext"/> <xsl:value-of select="$correction"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Ibve tried matching the text() in a separate template, but I canbt seem to reference the attribute values of the parent node (i.e., <word>) of the text() and the parent nodebs attributes. E.g, the following doesnbt work for me, failing somehow in the select=b../@correctionb reference. <xsl:template match=bword[@correction]/text()b> <xsl:value-of select=b../@correctionb/> </xsl:template> Any help would be much appreciated. ******************************** Kenneth R. Beesley, D.Phil. PO Box 540475 North Salt Lake UT 84054 USA
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