Re: [xsl] XPath expression which checks that a string is between 1 and 10 characters in length?

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

boolean(string-length(.)[. > 0 and . < 11)])

On Tue, Jul 26, 2016 at 6:30 AM, Eliot Kimber ekimber@xxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> How about:
>
> if (string(.) != '') then string-length(.) le 10 else false()
>
> That requires casting the context to a string twice but calculating string-length() once.
>
> Or
>
> matches(., '..?.?.?.?.?.?.?.?')
>
> (Can I do that with '..?{0,10}'? Reviewing the syntax it looked like the quantifier could only be a single digit.)
>
> Cheers,
>
> Eliot
>
>> On July 26, 2016 at 7:01 AM "Wolfgang Laun wolfgang.laun@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>>
>>
>> Just for fun:
>>
>> string-length() idiv 2 le 5
>>
>> Optimization by obfuscation. Phooey.
>> -W
>>
>> On 26 July 2016 at 13:55, Martin Honnen martin.honnen@xxxxxx <
>> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>>
>> > On 26.07.2016 13:51, Costello, Roger L. costello@xxxxxxxxx wrote:
>> >
>> > I need an XPath expression which returns true if the string in <A> is
>> >> between 1 and 10 characters in length, and false otherwise.
>> >>
>> >> For example, the XPath expression should return true on this XML:
>> >>
>> >>         <A>hi</A>
>> >>
>> >> Here's an inefficient XPath expression:
>> >>
>> >> (string-length(.) gt 0) and (string-length(.) le 10)
>> >>
>> >> It's inefficient because it computes the string length twice.
>> >>
>> >> Is there a more efficient XPath expression to solve this problem?
>> >>
>> >
>> > Well, in XPath 3 you can use
>> >
>> >   let $l := string-length()
>> >   return ($l gt 0 and $l le 10)
>> >
>> >
>> >
>>
> 



-- 
Cheers,
Dimitre Novatchev
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