Re: [xsl] Xslt string Operation

["Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Actually, you want OutFileName to be a function of fileHref and outDir, and
you are asking us to work out what that function does from one example of its
input and output. To do this properly we need to know what the possible range
of values of fileHref and outDir is: for example, is fileHref always a Windows
filename using forwards slashes to separate the parts of the path? Will it
always end in ".xml"? Or since it's a param, might someone pass in a filename
using backslashes, with no file extension?

I would encourage you to use URIs rather than filenames. You could then use
the resolve-uri() function for at least part of the task.

Michael Kay
Saxonica

> On 24 Aug 2016, at 17:16, Mailing Lists Mail daktapaal@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Dear all,
> I have the following two params
> <xsl:param name = bfileHrefb select = b
bP:/developers/perf/bigPayload.xmlb b/>
> <xsl:param name="outDir" select="'outDir'"/>
>
>   I want OutFileName to be :
bP:/developers/perf/outDir/bigPayload-Formatted.xmlb
>
> Is there a better way to do this than what I did?
> <xsl:variable name="OutFileName" select=" substring-before($fileHref,
tokenize($fileHref,'/')[last() -1 ] ) || $outDir || '/' ||   substring-before(
tokenize($fileHref,'/')[last()] ,'.xml') || '-Formatted.xml'"/>
>
> thanks.
> Dt
>
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