Re: [xsl] XPath for expressing contiguous elements?

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

And here is an XPath 2.0 expression:

empty(/*/B[. >> /*/A[1] and /*/A[last()] >> .])




On Mon, May 1, 2017 at 5:59 AM, Costello, Roger L. costello@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> Hi Folks,
>
> I want an XPath expression that implements this rule:
>
>         All <A> elements shall be contiguous within <Test>.
>
> In this example all A's are contiguous, so the rule is satisfied:
>
> <Test>
>     <B/>
>     <A/>
>     <A/>
>     <A/>
>     <B/>
> </Test>
>
> In this example there is an intervening B, so the rule is not satisfied:
>
> <Test>
>     <B/>
>     <A/>
>     <A/>
>     <B/>
>     <A/>
>     <B/>
> </Test>
>
> Below is the XPath that I created. I have two questions about it:
>
> (1) Is it correct? Do you see anything it would fail to catch?
>
> (2) Is there a better (simpler, more efficient) XPath expression?
>
> Here is the XPath (within a Schematron rule):
>
> <sch:rule context="Test">
>     <sch:assert test="
>         every $i in A satisfies
>            (if ($i/preceding-sibling::A) then $i/preceding-sibling::*[1][self::A] else true())
>            and
>            (if ($i/following-sibling::A) then $i/following-sibling::*[1][self::A] else true())
>         ">
>         All A's shall be contiguous within Test.
>     </sch:assert>
> </sch:rule>
> 



-- 
Cheers,
Dimitre Novatchev
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