Re: [xsl] Context in nested loop

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 28.07.2017 16:30, Joseph L. Casale jcasale@xxxxxxxxxxxxxxxxx wrote:

> Its schema is exactly the same as the sample XML, itbs a similar document
>
> with different values. To be honest, I whipped this repro up in vim so in reality
>
> the xpath selection within the message should correspond to the same element
>
> path I am iterating over but in the alternate document. In that case it should be
>
>
>
>      <xsl:value-of select="$document/root/nodeA/nodeB[@name=$name]/@*[local-name()=$attr]" />


So you have

    <xsl:for-each select="/root/nodeA/nodeB">
      <xsl:variable name="name" select="@name"/>
      <xsl:for-each select="@*">
        <xsl:variable name="attr" select="local-name()"/>
        <xsl:if test="name()!='name'">
          <xsl:message>
            <xsl:value-of 
select="$document/root/nodeA/nodeB[@name=$name]/@*[local-name()=$attr]" />
          </xsl:message>
        </xsl:if>
      </xsl:for-each>
    </xsl:for-each>

and of course the inner variable can be avoided with

    <xsl:for-each select="/root/nodeA/nodeB">
      <xsl:variable name="name" select="@name"/>
      <xsl:for-each select="@*">
        <xsl:if test="name()!='name'">
          <xsl:message>
            <xsl:value-of 
select="$document/root/nodeA/nodeB[@name=$name]/@*[local-name()=local-name(current())]" 
/>
          </xsl:message>
        </xsl:if>
      </xsl:for-each>
    </xsl:for-each>

and the outer with

    <xsl:for-each select="/root/nodeA/nodeB">
      <xsl:for-each select="@*">
        <xsl:if test="name()!='name'">
          <xsl:message>
            <xsl:value-of 
select="$document/root/nodeA/nodeB[@name=current()/../@name]/@*[local-name()=local-name(current())]" 
/>
          </xsl:message>
        </xsl:if>
      </xsl:for-each>
    </xsl:for-each>

if I am not mistaken.