Subject: Re: [xsl] XPath expression to express: There must be an empty sequence From: "Christoph Naber pentium120mhz@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 19 Nov 2017 19:47:59 -0000 |
For the set S with m elements list the n-tuples for n := [0, m] (https://en.wikipedia.org/wiki/Permutation#Permutations_with_repetition)
Best regards Christoph Naber
Hi Folks,
I have a set:
<set> <element>A</element> <element>B</element> </set>
Here are some sequences derived from the set:
<sequences> <sequence/> <sequence> <item>A</item> </sequence> <sequence> <item>B</item> </sequence> <sequence> <item>A</item> <item>A</item> </sequence> <sequence> <item>A</item> <item>B</item> </sequence> <sequence> <item>B</item> <item>A</item> </sequence> <sequence> <item>B</item> <item>B</item> </sequence> </sequences>
Notice that: - there is an empty sequence - there is a sequence corresponding to each element of the set - and there are other sequences (that I'm not concerned with for now)
I want to create XPath expressions which express the rules that sequences must satisfy to be valid.
First rule: There must be an empty sequence. I expressed that rule with this XPath expression:
sequence[not(item)]
Assume that the root element, <sequences>, is the context node.
Is that the right way to express the rule? Is there a better XPath expression? By "better" I mean simpler, plainer, more transparent. I seek simplicity and clarity over efficiency and cleverness.
Second rule: There must be a singleton sequence corresponding to every element in the set. A "singleton sequence" is a <sequence> containing one <item>.
I expressed that rule with this XPath expression:
every $element in $set//element satisfies exists(sequence[(item = $element) and not(item[2])])
Assume that $set is a variable whose value is the set.
Is that the right way to express the rule? Is there a better XPath expression?
/Roger
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