Subject: Re: [xsl] Using saxon:parse on processing instructions From: "Spencer Tickner spencertickner@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 18 Dec 2017 22:59:18 -0000 |
That did it, thank you so much Martin for the help. Cheers, Spencer On Mon, Dec 18, 2017 at 2:13 PM, Martin Honnen martin.honnen@xxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > On 18.12.2017 21:18, Spencer Tickner spencertickner@xxxxxxxxx wrote: > >> Hello and thanks in advance for the help. I'm scratching my head on >> trying to convert a string of serialized xml in a processing instruction >> back into XML. >> >> I'm restricted to XSLT 2.0 and am using Saxon 9.1. When I treat the >> simply copy and past the xml into the stylesheet everything works (see >> variable $s2), but when breaking the string out of the processing >> instruction the elements remain serialized: >> >> input: >> >> <?xml version="1.0"?> >> <root xmlns:bcl="http://bcl"> >> <?pi a="<bcl:e>Test</bcl:e>" ?> >> </root> >> > > A PI does not contain parsed character data so your data is double escaped. > > Does > > > <xsl:template match="processing-instruction('pi')"> > <root xmlns:bcl="http://example.com/bcl"><xsl:value-of > select="saxon:get-pseudo-attribute('a')" disable-output-escaping="yes"/ > ></root> > </xsl:template> > > > work with your version of Saxon? > > With Saxon 9.7 PE that gives > > <root xmlns:bcl="http://example.com/bcl"><bcl:e>Test</bcl:e></root
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