Subject: Re: [xsl] ordered selection of child elements From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 8 Mar 2018 06:54:06 -0000 |
Am 08.03.2018 um 07:36 schrieb Dr. Patrik Stellmann patrik.stellmann@xxxxxxxxx: > > Hi, > > a question more motivated by curiosity than by a real problem: > > With > > <xsl:sequence select=ba, bb/> > > I will get first element a and second element b b no matter of the > order within the input document. > > But with > > <xsl:sequence select=broot/(a, b)b/> > > I will get the elements a and b in document order. So this behaves > identical to > > B B B B B B B B B B B <xsl:sequence select=broot/(a | b)b/> > > Why? > > Of course I could write > > <xsl:sequence select=broot/a, root/bb/> > > To ensure a specific order. But sometimes the expression of brootb is > much more complex so Ibd like to avoid writing it twice or putting it > in a variableb& > You can move to XPath/XSLT 3 and use the "!" operator B root!(a, b)
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