Re: [xsl] for-each-group

["Rick Quatro rick@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

I just flipped Michael's solution around a bit and it seems to work fine:

 

group-adjacent="if (self::figure) then concat(local-name(),position()) else
0"

 

I forgot that you can use non-node values for grouping. XSLT is a great
language! Thanks again for the help.

 

Rick

 

From: Rick Quatro rick@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> 
Sent: Wednesday, March 28, 2018 12:23 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] for-each-group

 

OK, I think I get it. You are grouping on a string derived from the node
name instead of the node itself. This doesn't work for my general intent,
because the other elements may not all be the same. For example, I might
have this:

 

<steps>

  <step>

    <para>Intro stuff</para>

    <para>More intro stuff</para>

    <figure/>

    <figure/>

    <para>Conclusion stuff</para>

    <table>More conclusion stuff</table>

    <para>More conclusion stuff</para>

  </step>

</steps>

 

and I would want the three elements following the last figure to be in a
single group. But now that I see what you are doing, I will try to work it
out. Thanks.

 

Rick

 

From: Michael Kay mike@xxxxxxxxxxxx <mailto:mike@xxxxxxxxxxxx>
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx
<mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> > 
Sent: Wednesday, March 28, 2018 12:06 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <mailto:xsl-list@xxxxxxxxxxxxxxxxxxxxxx>

Subject: Re: [xsl] for-each-group

 

Try group-adjacent="concat(local-name(), if (self::figure) then position()
else 0))"

 

which will work for your example though it may not match your general
intent...

 

Michael Kay

Saxonica

 

 

On 28 Mar 2018, at 16:53, Rick Quatro rick@xxxxxxxxxxxxxx
<mailto:rick@xxxxxxxxxxxxxx>  <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx
<mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> > wrote:

 

Hi All,

 

I have a <step> element that looks something like this:

 

<steps>

  <step>

    <para>Intro stuff</para>

    <para>More intro stuff</para>

    <figure/>

    <figure/>

    <para>Conclusion stuff</para>

    <para>More conclusion stuff</para>

  </step>

</steps>

 

I want 4 separate groups:

 

1) First two <para> elements.

2) First <figure>

3) Second <figure>

4) Last two <para> elements.

 

Here is my stylesheet:

 

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl=" <http://www.w3.org/1999/XSL/Transform>
http://www.w3.org/1999/XSL/Transform";

    xmlns:xs=" <http://www.w3.org/2001/XMLSchema>
http://www.w3.org/2001/XMLSchema";

    exclude-result-prefixes="xs"

    version="2.0">

    

    <xsl:template match="/steps">

        <xsl:apply-templates select="step"/>

    </xsl:template>

    

    <xsl:template match="step">

        <xsl:for-each-group select="*" group-starting-with="figure">

            <xsl:message select="count(current-group())"></xsl:message>

        </xsl:for-each-group>

    </xsl:template>

    

</xsl:stylesheet>

 

I get the first two groups, but the last two <para> elements are part of the
last <figure>'s group instead of being separate.

 

I tried using group-by="figure" but I don't get any output. Any help would
be appreciated. Thank you very much.

 

Rick

 

Rick Quatro

Carmen Publishing Inc.

 <mailto:rick@xxxxxxxxxxxxxxx> rick@xxxxxxxxxxxxxxx

FrameMaker toys:  <http://www.frameexpert.com/store>
www.frameexpert.com/store

585-366-4017

 

 

 

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